You need to wrap a present that you will put inside a cylindrical container. You’ll need to know how much will fit in the container and how much wrapping paper you will need. The container stands 7 inches high and has a diameter of 5 inches. Draw a net of the container and solve for the volume and total surface area of the container. (Use 3.14 for Π )PLEASE SHOW ALL WORK!!!!!!!!!!!!
Accepted Solution
A:
Answer:149.28 sq. inches137.5 cubic inches.Step-by-step explanation:The cylindrical container has length or height (h) 7 inches and has a diameter of 5 inches i.e. radius (r) 2.5 inches.
Now, total surface area of the container = [tex]2\pi r^{2} + 2\pi rh[/tex]
= [tex]\frac{2 \times 22 \times (2.5)^{2} }{7} + \frac{2 \times 22 \times 2.5 \times 7}{7}[/tex]
= 39.28 + 110 = 149.28 sq. inches (Answer)
Again the volume of the container will be [tex]\pi r^{2}h[/tex]
= [tex]\frac{22 \times (2.5)^{2} \times 7}{7}[/tex]
= 137.5 cubic inches. (Answer)