​You need to wrap a present that you will put inside a cylindrical container. You’ll need to know how much will fit in the container and how much wrapping paper you will need. The container stands 7 inches high and has a diameter of 5 inches. ​Draw a net​ of the container and solve for the volume​ and ​total surface area​ of the container. (Use 3.14 for Π )PLEASE SHOW ALL WORK!!!!!!!!!!!!

Accepted Solution

Answer:149.28 sq. inches137.5 cubic inches.Step-by-step explanation:The cylindrical container has length or height (h) 7 inches and has a diameter of 5 inches i.e. radius (r) 2.5 inches. Now, total surface area of the container = [tex]2\pi r^{2} + 2\pi rh[/tex] = [tex]\frac{2 \times 22 \times (2.5)^{2} }{7} + \frac{2 \times 22 \times 2.5 \times 7}{7}[/tex] = 39.28 + 110  = 149.28 sq. inches (Answer) Again the volume of the container will be [tex]\pi r^{2}h[/tex] = [tex]\frac{22 \times (2.5)^{2} \times 7}{7}[/tex] = 137.5 cubic inches. (Answer)